📑 3D Printing

Codejam Qualification Round 2022. Task 2

Python Only

T=int(input())
for t in range(T):
    C,M,Y,K=[],[],[],[]
    for i in range(3):
        N=input()
        N=[int(n) for n in N.split()]
        C+=[N[0]]; M+=[N[1]]; Y+=[N[2]]; K+=[N[3]]
    c,m,y,k=min(C),min(M),min(Y),min(K)
    if c+m+y+k<10**6:
        R='IMPOSSIBLE'
    else:
        m=min([m,10**6-c])
        y=min([y,10**6-c-m])
        k=10**6-c-m-y
        R='{} {} {} {}'.format(c,m,y,k)
    print('Case #{}: {}'.format(t+1,R))

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@interact

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def ddd_printing(

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    T=slider([1,2,3],default=1),

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    N1=input_box('300000 200000 300000 500000\n'+\

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                 '1000000 1000000 0 0\n'+\

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                 '768763 148041 178147 984173',

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                 type=str,label='N1',width=30,height=3),

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    N2=input_box('300000 200000 500000 300000\n'+\

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                 '0 1000000 1000000 1000000\n'+\

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                 '699508 515362 534729 714381',

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                 type=str,label='N2',width=30,height=3),

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    N3=input_box('300000 500000 300000 200000\n'+\

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                 '999999 999999 999999 999999\n'+\

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                 '949704 625054 946212 951187',

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                 type=str,label='N3',width=30,height=3)):

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    N1=str(N1).split('\n')

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    N2=str(N2).split('\n')

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    N3=str(N3).split('\n')

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    NN=[[N1[i],N2[i],N3[i]] for i in range(3)]

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    print('C M Y K:')

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    [print(el) for el in NN[T-1]+['\n']]

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    C,M,Y,K=[],[],[],[]

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    for i in range(3):

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        N=[int(n) for n in NN[T-1][i].split()]

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        C+=[N[0]]; M+=[N[1]]; Y+=[N[2]]; K+=[N[3]]  

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    c,m,y,k=min(C),min(M),min(Y),min(K)

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    if c+m+y+k<10**6:

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        R='IMPOSSIBLE'

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    else:

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        m=min([m,10**6-c])

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        y=min([y,10**6-c-m])

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        k=10**6-c-m-y

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        R='{} {} {} {}'.format(c,m,y,k)

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    print('Case #{}: {}'.format(T,R))

Language: Sage Gap GP HTML Macaulay2 Maxima Octave Python R Singular

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